Reading facts is the most common question types in McKinsey PST (38%). These questions test your ability to understand the fact / data itself. There will be no inferring, logic, hypothesizing, or creativity needed. See the illustrating picture below.

## Word Problem Practice

All questions are word problem questions. This question type represents about 8% of all questions on the McKinsey Problem Solving Test. In this sample practice, you should aim for 2/2 correct answers.

## Root-cause Reason Practice

All questions are root-cause questions. This question type represents about 13% of all questions on the McKinsey Problem Solving Test. This question is written based on an official McKinsey practice PST question.

## Formulae Practice

All questions are formulae questions. This question type represents about 5% of all questions on the McKinsey Problem Solving Test. This question is written based on an official McKinsey practice PST question.

## Client Interpretation Practice

All questions are client interpretation  questions. This question type represents about 8% of all questions on the McKinsey Problem Solving Test. This question is written based on an official McKinsey practice PST question.

## Fact-based Conclusion Practice

All questions are fact-based conclusion questions. This question type represents about 14% of all questions on the McKinsey Problem Solving Test. This question is written based on an official McKinsey practice PST question.

• Joana

Hello! Can I have some feedback regarding Question 2 of Word Problem Practice? Here’s my logic, for 1 month:
Cost = Benefit = 200 k\$
Benefit = 100\$*(Computers sold) = 100\$*(New Conversion Rate)*(Visitors) = 100\$*(1.2*0.05)*(Visitors)
200 k\$ = 100\$*0.06*Visitors Visitors = 33 000 => Minimum wold be answer A (100 000 visitors), but apparently is answer B (200 000)!
Did I misinterpreted something ?
Thank you !

• Alex Hunt

For the campaign to be considered profitable, it has to generate \$200,00 on its own, completely separate from the sale that the retailer is already pulling in.
The campaign raises the conversion rate from 5% to 6%, which means it creates an extra \$1 per customer.
From there, we can see that the retailer needs at least 200,000 visits to make the campaign profitable.

• Taher

You’ve missed an important assumption here that there were expenses before the marketing campaign as well.
Let the number of visitations be x, and n be the overall expense before marketing campaign.
So we have x*5%*\$100 = n ( to break even)
After the marketing expense
x*5%*120%*\$100 = n + \$200,000
solving for x we get 200,000 visits.